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Why gold carbenes hit phenol para-C–H

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DFT plus deuterium controls show (PhO)3PAu carbenes add at phenol para-C, then two waters shuttle the proton, beating O–H insertion.

Source

Origins of unique gold-catalysed chemo- and site-selective C-H functionalization of phenols with diazo compounds

Liu Y, Yu Z, Zhang JZ, et al. · Chemical science · 2016

doi.org/10.1039/c5sc04319kRead the full paper ↗59 citationscc by

What they did

They computed free-energy profiles for gold-carbene addition to phenol with (PhO)3P versus Ph3P ligands, compared C–H versus O–H insertion, and tested water-assisted proton transfer against a direct [1,2]-H shift. Control reactions with deuterated phenol supported the water-shuttle pathway.

What they found

Au-carbene formation is cheap (6.5 and 11.4 kcal mol–1). Para addition (15.6 kcal mol–1) beats ortho (19.3) and meta (23.6). Direct [1,2]-H shift is 30.1 kcal mol–1, while a two-water shuttle is favored. The C–H product is 10.8 kcal mol–1 more stable than the O–H insertion product. Switching to Ph3P raises the C–H addition barrier and lowers the O–H barrier.

The limits

What it doesn't show

The computed barriers are IEFPCM solution free energies at 298 K, not measured rates. Only phenol/α-diazoester systems are mapped, so the water-shuttle model is not proven for other arenes or metals. Isolated product yields for a broad substrate table are not the focus.

Key terms

Gold carbene
Electrophilic Au=CR2 species formed when a gold catalyst decomposes a diazo compound by losing N2.
Chemoselectivity
Which bond reacts: here aromatic C–H insertion versus phenolic O–H insertion.
Proton shuttle
Water molecules that relay a proton between sites instead of a concerted intramolecular hydride shift.
Enol intermediate
After para addition, a gold-bound enol forms before tautomerization to the ketone-like C–H product.
[1,2]-H shift
Direct migration of hydrogen to an adjacent carbon; calculated here as too high in energy.

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Which site of phenol is computed as most favorable for gold-carbene C–C coupling with (PhO)3P?

Common questions

Why does para-C–H beat O–H insertion with (PhO)3PAu?

The C–H intermediates and product are more stable, and the water-assisted hydrogen transfer is lower in energy than the O–H path.

What does water do?

Two water molecules shuttle the proton from the enol to the final C–H product; a direct [1,2]-H shift is ~30 kcal mol–1.

How does the phosphite ligand help?

Oxygen atoms on (PhO)3P hydrogen-bond to the shuttle waters and stabilize that transition state.

What happens with Ph3P instead?

C–H addition gets harder and O–H insertion gets easier, matching the ligand-dependent chemoselectivity.

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